Sodium hydride → HCID 86687103, compound

HRID 1402251Notes

Reaction equation

HRID 1402251 reaction equation
[H-].[Na+].[NH2:3][C@@H:4]1[C:13]2[C:8](=[CH:9][CH:10]=[CH:11][CH:12]=2)[C@H:7]([OH:14])[CH2:6][CH2:5]1.F[C:16]1[CH:17]=[CH:18][C:19]2[N:20]([C:22]([C:25]([CH3:32])([N:27]3[CH2:31][CH2:30][CH2:29][CH2:28]3)[CH3:26])=[N:23][N:24]=2)[CH:21]=1>CN(C=O)C>[CH3:32][C:25]([C:22]1[N:20]2[CH:21]=[C:16]([O:14][C@H:7]3[C:8]4[C:13](=[CH:12][CH:11]=[CH:10][CH:9]=4)[C@@H:4]([NH2:3])[CH2:5][CH2:6]3)[CH:17]=[CH:18][C:19]2=[N:24][N:23]=1)([N:27]1[CH2:28][CH2:29][CH2:30][CH2:31]1)[CH3:26]

Participants

5

Conditions

Temperature
60 °C

Procedure

To a suspension of NaH (60% in mineral oil, 135 mg, 3.37 mmol) in DMF (4.50 mL) was added Intermediate A (137 mg, 0.84 mmol) and the reaction stirred for 20 min. Intermediate 80b (209 mg, 0.84 mmol) was added in DMF (1.50 mL) and the reaction heated to 60° C. for 1 h. The reaction was cooled and quenched by dropwise addition of methanol, before being diluted with methanol and loaded onto an SCX-2 cartridge, which was washed with MeOH and product eluted with 2M NH3 in MeOH. The resulting residue was purified by FCC, using 0-10% [2M NH3 in MeOH] in DCM, to give the title compound (180 mg, 55%). LCMS (Method 4): Rt 0.31, m/z 392.2 [MH+].

Workup

  1. temperatureThe reaction was cooled
  2. customquenched by dropwise addition of methanol
  3. additionbefore being diluted with methanol
  4. washwas washed with MeOH and product
  5. washeluted with 2M NH3 in MeOH
  6. customThe resulting residue was purified by FCC

Sources & evidence

ORD record
ord-bc47864712c444869b420e3258811626
Source dataset
uspto-grants-2014_12
Patent number
US08907094B2

Reaction notes

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