Sulfite → Sulfite
Reaction equation
[S:1]([O-:4])([O-:3])=[O:2].[OH-:5].[Na+]>>[S:1]([O-:4])([O-:3])=[O:2].[S:1]([O-:5])([O-:4])(=[O:3])=[O:2]Participants
4
Procedure
FOr oxidation down to 1 g Na2S per liter black liquor, the black liquor consmues 39 liters of air per liter black liquor, while sulphite from soap splitting reduces the air demand to 18 liter per liter black liquor. For these points the alkalinity values of the black liquors are 4.5 g NaOH/liter and 8.0 g NaOH/liter, respectively. Alkali useful for the neutralization of the sulphite solution is thus produced by the reaction between sulphite and sulphide while sulphate from conventional sulphuric splitting solution is not at all capable of oxidizing the sulphide or to react with any other sulphur compound.
Sources & evidence
- ORD record
- ord-1a8d682f6bf64839a5e2db6423920e6a
- Source dataset
- uspto-grants-1977_01
- Patent number
- US04005060
Reaction notes
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