Acetone → 3E,5E-Pseudoionone
Reaction equation
[CH3:1][C:2](=[CH:4][CH2:5][CH2:6][C:7](=[CH:9][CH:10]=O)[CH3:8])[CH3:3].[CH3:12][C:13]([CH3:15])=[O:14]>[Cu]=O.[O-2].[Zn+2]>[CH3:3][C:2]([CH3:1])=[CH:4][CH2:5][CH2:6]/[C:7](/[CH3:8])=[CH:9]/[CH:10]=[CH:12]/[C:13]([CH3:15])=[O:14]Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
50 Parts of citral and 100 parts of acetone are reacted for 45 minutes at 200° C and a pressure of 80 atmospheres in the presence of 12 parts of a catalyst consisting of 12% by weight of copper(II) oxide and 88% by weight of zinc oxide. 45.6 parts of pseudoionone having a boiling point of 90° C at 0.01 mm is obtained analogously to Example 1. The conversion is 82% of theory and the yield based on citral is 88% of theory.
Sources & evidence
- ORD record
- ord-6328ca294a1e4aa4be8365f859c4aa9b
- Source dataset
- uspto-grants-1977_01
- Patent number
- US04005147
Reaction notes
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