Hydrochloric Acid → HCID 53796098, compound

HRID 1415969Notes

Reaction equation

Cl.C([O:4][C:5]([C:7]1[C:16](=[O:17])[C:15]2[C:10](=[C:11]([F:28])[C:12]([F:27])=[C:13]([F:26])[C:14]=2[O:18]CC2C=CC=CC=2)[N:9]([C:29]2[C:34]([F:35])=[CH:33][C:32]([F:36])=[C:31]([NH:37]C(OCC3C=CC=CC=3)=O)[CH:30]=2)[CH:8]=1)=[O:6])C>C(O)(=O)C>[NH2:37][C:31]1[CH:30]=[C:29]([N:9]2[C:10]3[C:15](=[C:14]([OH:18])[C:13]([F:26])=[C:12]([F:27])[C:11]=3[F:28])[C:16](=[O:17])[C:7]([C:5]([OH:6])=[O:4])=[CH:8]2)[C:34]([F:35])=[CH:33][C:32]=1[F:36]

Participants

Conditions

Temperature: 100 °C

Procedure

To 8 ml of acetic acid and 10 ml of 6N hydrochloric acid was added 1.3 g of the compound synthesized in Example 235. The solution was stirred at 100° C. for 4 hours. The solvent was distilled off in vacua. Water was added to the residue. The solid was collected by filtration and washed with water, ethanol, and isopropyl ether to give 0.55 g of the title compound as a yellow solid.

Workup

distillationThe solvent was distilled off in vacua
additionWater was added to the residue
filtrationThe solid was collected by filtration
washwashed with water, ethanol, and isopropyl ether

Sources & evidence

ORD record: ord-a925b4fca5024d60bfac470ea4c978c0
Source dataset: uspto-grants-1999_06
DOI: 10.6084/m9.figshare.5104873.v1
Patent number: US05910498

Reaction notes

Loading…