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HRID1448080

反应详情

EQUATION

反应方程式

HRID 1448080 的结构方程式

REACTANTS

反应物

4
结构：CC(C)OC(C)C
HCID7914

Isopropyl ether

C6H14O

结构：CCN(CC)CC
HCID8471

Triethylamine

C6H15N

结构：CC(C)C(=O)C(C)(C)SN(C)C(=O)Cl
HCID54024146

未命名化合物

结构：CN1C(=O)C(C)(C)SC1=NO
HCID71363389

2-(Hydroxyimino)-3,5,5-trimethyl-1,3-thiazolidin-4-one

C6H10N2O2S

PRODUCTS

生成物

1
结构：CC(C)C(=O)C(C)(C)SN(C)C(=O)ON=C1SC(C)(C)C(=O)N1C
HCID54245956

未命名化合物

收率 39.6%

AUXILIARIES

试剂、催化剂与溶剂

1
结构：C1COCCO1
溶剂HCID31275

1,4-Dioxane

C4H8O2

PROCEDURE

实验过程

Prepared as in Example I by reacting 2.94 g (0.0169 m) of 3,5,5-trimethyl-2-oximino-thiazolidin-4-one, 4.0 g (0.0169 m) of N-methyl-N-(2,4-dimethyl-3-oxo-2-pentanesulfenyl)carbamoyl chloride and 1.7 g (0.0169 m) of triethylamine in 200 ml of dioxane. The productcrystallized from isopropyl ether to yield 2.5 g of a white solid, m.p. 112°-114° C.

WORKUP

后处理

  1. customPrepared as in Example I