HRID1460245

反应详情

EQUATION

反应方程式

HRID 1460245 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

3

PROCEDURE

实验过程

A mixture of 15.05 g (0.048 mole) of α,α-bis(4-fluorophenyl)-4-pyridineethanol, 3.2 g (0.1 mole) of phosphorus and 50 ml of 56.9% hydrogen iodide in 150 ml of glacial acetic acid was heated at reflux for 11 hr. The solvent was removed in vacuo, and the residue was partitioned between methylene chloride and dilute sodium hydroxide. The methylene chloride solution was dried over magnesium sulfate, and the solvent was removed in vacuo to give an oil. This was dissolved in a mixture of methanol and ether, and an excess of ethereal hydrogen chloride was added. The solvent was removed in vacuo, and the residue was recrystallized from a mixture of acetonitrile and ether to give 13.89 g (87% yield) of title compound as a white, crystalline solid, mp 197°-199° C.

WORKUP

后处理

  1. temperaturewas heated
  2. temperatureat reflux for 11 hr
  3. customThe solvent was removed in vacuo
  4. customthe residue was partitioned between methylene chloride and dilute sodium hydroxide
  5. dry with materialThe methylene chloride solution was dried over magnesium sulfate
  6. customthe solvent was removed in vacuo
  7. customto give an oil
  8. customThe solvent was removed in vacuo
  9. customthe residue was recrystallized from a mixture of acetonitrile and ether