HRID1462430

反应详情

EQUATION

反应方程式

HRID 1462430 的结构方程式

PROCEDURE

实验过程

11.0 g of N-(2-chlorobenzoyl)-N-[(3-thienylcarbonyl)methyl]amine, 2.17 g of 50% sodium hydride and 7.9 g of ethyl bromoacetate are treated in the same manner as described in Preparation 1-(4). 14 g of ethyl 3-(2-chlorobenzoylamino)-3-(3-thienylcarbonyl)propionate are thereby obtained as an oil. Yield: 97.2%

WORKUP

后处理

  1. customas described in Preparation 1-(4)