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HRID14641

反应详情

EQUATION

反应方程式

HRID 14641 的结构方程式

REACTANTS

反应物

2
结构：Cl
HCID313

Hydrochloric Acid

ClH

结构：COc1cc(OC)c2c(CNC(=O)OC(C)(C)C)ncc(C(=O)N(C)Cc3cccnc3)c2c1
HCID68614078

未命名化合物

PRODUCTS

生成物

1
结构：COc1cc(OC)c2c(CN)ncc(C(=O)N(C)Cc3cccnc3)c2c1.Cl
HCID68614784

未命名化合物

收率 100%

AUXILIARIES

试剂、催化剂与溶剂

1
结构：CCOC(C)=O
溶剂HCID8857

Ethyl acetate

C4H8O2

PROCEDURE

实验过程

As described in example 1, 88 mg of [6,8-dimethoxy-4-(methyl-pyridin-3-ylmethyl-carbamoyl)-isoquinolin-1-ylmethyl]-carbamic acid tert-butyl ester was treated with HCl in EtOAc to give 102 mg (>100%) of 1-aminomethyl-6,8-dimethoxy-isoquinoline-4-carboxylic acid methyl-pyridin-3-ylmethyl-amide hydrochloride. MS: APCI (M+H) calc'd for C21H24N4O3+H 381.4; found 381.2.