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HRID14688

反应详情

EQUATION

反应方程式

HRID 14688 的结构方程式

REACTANTS

反应物

2
结构：Cl
HCID313

Hydrochloric Acid

ClH

结构：COc1cc2c(CC(=O)N(C)CCc3ccccn3)cnc(CNC(=O)OC(C)(C)C)c2cc1OC
HCID68614425

未命名化合物

PRODUCTS

生成物

1
结构：COc1cc2c(CC(=O)N(C)CCc3ccccn3)cnc(CN)c2cc1OC.Cl
HCID68616047

未命名化合物

收率 100%

AUXILIARIES

试剂、催化剂与溶剂

1
结构：CCOC(C)=O
溶剂HCID8857

Ethyl acetate

C4H8O2

PROCEDURE

实验过程

As described in Example 1, 78 mg of (6,7-dimethoxy-4-{[methyl-(2-pyridin-2-yl-ethyl)-carbamoyl]-methyl}-isoquinolin-1-ylmethyl)-carbamic acid tert-butyl ester was treated with HCl in EtOAc to give 86 mg (>100%) of 2-(1-aminomethyl-6,7-dimethoxy-isoquinolin-4-yl)-N-methyl-N-(2-pyridin-2-yl-ethyl)-acetamide hydrochloride. MS: APCI (M+H) calc'd for C22H26N4O3+H 395.5; found 395.1.