4-(Bromomethyl)benzonitrile → HCID 118113395, compound

HRID 1485101Notes

Reaction equation

HRID 1485101 reaction equation
FC(F)(F)C1N=CC([OH:9])=CC=1.C(C1C=CC(CBr)=CC=1)#N.[OH:22][CH2:23][C:24]1[CH:31]=[CH:30][C:27]([C:28]#N)=[CH:26][CH:25]=1.F[C:33]1[CH:38]=[CH:37][C:36]([C:39]([F:42])([F:41])[F:40])=[CH:35][N:34]=1>>[F:40][C:39]([F:42])([F:41])[C:36]1[CH:37]=[CH:38][C:33]([O:22][CH2:23][C:24]2[CH:31]=[CH:30][C:27]([CH:28]=[O:9])=[CH:26][CH:25]=2)=[N:34][CH:35]=1

Participants

5

Reactant 4

HCID 869964-(Bromomethyl)benzonitrileHCID 160549p-Cyanobenzyl alcoholHCID 27833885-Hydroxy-2-(trifluoromethyl)pyridineHCID 54637542-Fluoro-5-(trifluoromethyl)pyridine

Product 1

HCID 118113395HCID 118113395, compound

Procedure

Instead of 6-(trifluoromethyl)pyridin-3-ol and 4-cyanobenzylbromide, 4-(hydroxymethyl)benzonitrile (1.87 g) and 2-fluoro-5-(trifluoromethyl)pyridine (1.55 g) were respectively used and treated by the same technique as in Reference Example 38-1 to give the titled compound as a pale yellow solid (1.49 g).

Workup

  1. additiontreated by the same technique as in Reference Example 38-1

Sources & evidence

ORD record
ord-384ba5c0d3c44f748ffb32bc3f8d1a6d
Source dataset
uspto-grants-2016_08
Patent number
US09422240B2

Reaction notes

Loading…