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HRID1589235

反应详情

EQUATION

反应方程式

HRID 1589235 的结构方程式

REACTANTS

反应物

3
结构：Cl
HCID313

Hydrochloric Acid

ClH

结构：C=O
HCID712

Formaldehyde

CH2O

结构：CCCCCCO
HCID8103

1-Hexanol

C6H14O

PRODUCTS

生成物

1
结构：CCCCCCOCCl
HCID12546512

1-(Chloromethoxy)hexane

C7H15ClO

AUXILIARIES

试剂、催化剂与溶剂

1
结构：ClCC(Cl)Cl
溶剂HCID6574

1,1,2-Trichloroethane

C2H3Cl3

PROCEDURE

实验过程

30 g (1 mole) of paraformaldehyde were stirred in 100 ml of 1,1,2-trichloroethane with 102 g (1 mole) of 1-hexanol at 0°-5° C. HCl gas was passed for 2 hours. The product is diluted to give a stock solution of 3M concentration.

WORKUP

后处理

  1. additionThe product is diluted
  2. customto give
  3. concentrationa stock solution of 3M concentration