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HRID1608460

反应详情

EQUATION

反应方程式

HRID 1608460 的结构方程式

REACTANTS

反应物

3
结构：OC[C@H]1O[C@@](CO)(O[C@H]2O[C@H](CO)[C@@H](O)[C@H](O)[C@H]2O)[C@@H](O)[C@@H]1O
HCID5988

Sucrose

C12H22O11

结构：[Na+].[Na+].[O]=[Cr](=[O])([O-])[O-]
HCID24488

Sodium chromate

CrNa2O4

结构：O=S(=O)([O-])O.[Na+]
HCID516919

Sodium hydrogen sulfate

HNaO4S

PRODUCTS

生成物

1
结构：O=S(=O)([O-])[O-].O=S(=O)([O-])[O-].O=S(=O)([O-])[O-].[Cr+3].[Cr+3]
HCID24930

Chromium sulfate (Cr2(SO4)3)

Cr2O12S3

PROCEDURE

实验过程

The neutral solution of sodium chromate was poured into an acidating tank, and again the above-mentioned sodium hydrogen sulfate was added, to neutralize to Ph=1.5-2.0, which converted Na2CrO4 to Na2Cr2O7. Next, 2.181 Kg of sucrose crystals were added slowly while continuously agitating to form basic chromium sulfate. No Cr+6 was detected indicating that the reductive reaction had proceeded to completion.