Lithium Hydroxide → HCID 67036415, compound
Reaction equation
C[O:2][C:3](=[O:30])[C:4]1[CH:9]=[CH:8][CH:7]=[C:6]([CH2:10][N:11]2[C:19]3[C:14](=[CH:15][CH:16]=[CH:17][CH:18]=3)[C:13](=[C:20]([C:22]3[CH:27]=[CH:26][C:25]([F:28])=[CH:24][CH:23]=3)[CH3:21])[C:12]2=[O:29])[CH:5]=1.[OH-].[Li+]>C1COCC1.O>[F:28][C:25]1[CH:24]=[CH:23][C:22]([C:20](=[C:13]2[C:14]3[C:19](=[CH:18][CH:17]=[CH:16][CH:15]=3)[N:11]([CH2:10][C:6]3[CH:5]=[C:4]([CH:9]=[CH:8][CH:7]=3)[C:3]([OH:30])=[O:2])[C:12]2=[O:29])[CH3:21])=[CH:27][CH:26]=1Participants
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
A solution of 3-{3-[1-(4-fluoro-phenyl)-ethylidene]-2-oxo-2,3-dihydro-indol-1-ylmethyl}-benzoic acid methyl ester (0.33 g, 0.82 mmol) was dissolved in THF 5 ml. Then a solution of lithium hydroxide (0.35 g, 8.2 mmol) in water (2.0 ml) was added. After stirring for 12 hours, the solvent was removed under reduced pressure. The residue was dissolved in 2 ml DMF for prepared HPLC to give 3-{3-[1-(4-fluoro-phenyl)-ethylidene]-2-oxo-2,3-dihydro-indol-1-ylmethyl}-benzoic acid as yellow powder (100 mg). 1H NMR (400 MHz, DMSO-d6) δ ppm 2.78 (s, 3H) 5.06 (s, 2H) 6.08 (d, J=7.83 Hz, 1H) 6.68 (t, J=7.45 Hz, 1H) 6.92 (d, J=7.83 Hz, 1H) 7.11 (t, J=7.45 Hz, 1H) 7.38 (t, J=8.84 Hz, 2H) 7.43-7.51 (m, 1H) 7.46 (dd, J=8.72, 5.68 Hz, 2H) 7.60 (d, J=7.58 Hz, 1H) 7.85 (d, J=7.83 Hz, 1H) 7.92 (s, 1H) 13.03 (s, 1H). MS calcd. for C24H18FNO3 387.4, obsd. (ESI+) [(M+H)+] 388.2.
Workup
- customthe solvent was removed under reduced pressure
- dissolutionThe residue was dissolved in 2 ml DMF
- customfor prepared HPLC
Sources & evidence
- ORD record
- ord-0d39b84786324e2a85dcec9ecf80b75c
- Source dataset
- uspto-grants-2014_07
- Patent number
- US08778973B2
Reaction notes
Loading…