Potassium Iodide → Hydrochloric Acid

HRID 1639094Notes

Reaction equation

HRID 1639094 reaction equation
[CH3:1][C:2]1[CH:7]=[CH:6][C:5]([N:8]2[CH2:13][CH2:12][NH:11][CH2:10][CH2:9]2)=[CH:4][CH:3]=1.[Cl:14][CH2:15][CH2:16][CH:17]([OH:27])[CH2:18][O:19][C:20]1[CH:25]=[CH:24][C:23]([F:26])=[CH:22][CH:21]=1.C(=O)([O-])[O-].[Na+].[Na+].[I-].[K+]>CC(O)C.C(O)CCC>[ClH:14].[ClH:14].[F:26][C:23]1[CH:24]=[CH:25][C:20]([O:19][CH2:18][CH:17]([OH:27])[CH2:16][CH2:15][N:11]2[CH2:12][CH2:13][N:8]([C:5]3[CH:4]=[CH:3][C:2]([CH3:1])=[CH:7][CH:6]=3)[CH2:9][CH2:10]2)=[CH:21][CH:22]=1.[ClH:14]

Participants

8

Reactant 4

HCID 4875Potassium IodideHCID 10340Sodium CarbonateHCID 831131-(p-Tolyl)piperazineHCID 14422830HCID 14422830, compound

Product 2

HCID 313Hydrochloric AcidHCID 19840251HCID 19840251, compound

Reagents, catalysts & solvents 2

HCID 2631-ButanolSolventHCID 3776IsopropanolSolvent

Procedure

This compound was prepared according to the procedure of Example 25. A mixture of 1.8 g (0.01 mole) of 1-(4-methylphenyl)piperazine, 2.2 g (0.01 mole) of 4-chloro-1-(4-fluorophenoxy)-2-butanol, 5.2 g (0.05 mole) of anhydrous sodium carbonate, and 0.1 g of potassium iodide in a total volume of 200 ml of 1-butanol gave a golden oil as residue. The hydrochloride was formed in 2-propanol saturated with hydrogen chloride and the collected solid was recrystallized from methanol-water-ethyl ether to give 1.8 g (41%) of white solid, m.p. 200°-205° C.

Workup

  1. customThis compound was prepared
  2. customgave a golden oil as residue

Sources & evidence

ORD record
ord-cacceb7ea78b46b2ac7d14254d866bb8
Source dataset
uspto-grants-1989_11
Patent number
US04882330

Reaction notes

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