2,6-Lutidine → HCID 13882879, compound
Reaction equation
[Cl:1][C:2]([F:20])([F:19])[C:3]1[N:8]=[C:7]([C:9]([F:12])([F:11])[F:10])[C:6]([C:13]([O:15][CH2:16][CH3:17])=[O:14])=[C:5](O)[CH:4]=1.N1C(C)=CC=CC=1C.P(Cl)(Cl)([Cl:31])=O>>[Cl:31][C:5]1[CH:4]=[C:3]([C:2]([Cl:1])([F:20])[F:19])[N:8]=[C:7]([C:9]([F:12])([F:11])[F:10])[C:6]=1[C:13]([O:15][CH2:16][CH3:17])=[O:14]Participants
4
Procedure
This compound was prepared as described in Example 9: 75 g (0.235 mol) of product of Example 3, 50.29 g (55 ml, 0.469 mol) of 2,6-lutidine and 252.66 g (214 ml, 2.3 mol) of phosphorus oxychloride were reacted affording 68 g of a black oil. The crude product was purified by kugelrohr distillation at 200 Pa, pot temperature 110° C., to give 48 g (60%) of product as a yellow oil, nD25 1.4466.
Workup
- customThis compound was prepared
Sources & evidence
- ORD record
- ord-f3a059c8ae1048a6a0c3cd061e1c7862
- Source dataset
- uspto-grants-1990_05
- Patent number
- US04921530
Reaction notes
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