HCID 86638407, compound → HCID 86638409, compound
Reaction equation
[CH2:1]([O:3][P:4]([C:9]1[C:13]([P:14]([O:19][CH2:20][CH3:21])([O:16][CH2:17][CH3:18])=[O:15])=[CH:12][S:11][C:10]=1I)([O:6][CH2:7][CH3:8])=[O:5])[CH3:2].C([Sn](CCCC)(CCCC)[C:28]1[S:29][CH:30]=[C:31]([P:41]([O:46][CH2:47][CH3:48])([O:43][CH2:44][CH3:45])=[O:42])[C:32]=1[P:33]([O:38][CH2:39][CH3:40])([O:35][CH2:36][CH3:37])=[O:34])CCC>C1COCC1.[Cu]Cl>[CH2:1]([O:3][P:4]([C:9]1[C:13]([P:14]([O:19][CH2:20][CH3:21])([O:16][CH2:17][CH3:18])=[O:15])=[CH:12][S:11][C:10]=1[C:28]1[S:29][CH:30]=[C:31]([P:41]([O:43][CH2:44][CH3:45])([O:46][CH2:47][CH3:48])=[O:42])[C:32]=1[P:33]([O:35][CH2:36][CH3:37])([O:38][CH2:39][CH3:40])=[O:34])([O:6][CH2:7][CH3:8])=[O:5])[CH3:2]Participants
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
In THF, 0.037 g (0.076 mmols) of the 2-iodo-3,4-bis(diethoxyphosphoryl)thiophene obtained in Example 4 and 0.049 g (0.076 mmols) of the 2-tributylstannyl-3,4-bis(diethoxyphosphoryl)thiophene obtained in Example 5 were dissolved, to which 0.009 g (0.091 mmols) of commercially available copper(I) chloride was added at room temperature. Thereafter, the reaction mixture was heated and stirred for 4 hours under reflex. After the reaction, the reaction mixture was cooled down to room temperature and the resulting solid was removed by celite filtration. The filtrate was distilled off under reduced pressure to remove the solvent, and the resulting crude product was purified with a silica gel column (ethyl acetate:methanol=15:1 to ethyl acetate:methanol=5:1) to obtain the specified substance in the form of a transparent oil at a yield of 0.049 g (yield: 91%).
Workup
- additionwas added at room temperature
- temperatureThereafter, the reaction mixture was heated
- customAfter the reaction
- customthe resulting solid was removed by celite filtration
- distillationThe filtrate was distilled off under reduced pressure
- customto remove the solvent
- customthe resulting crude product was purified with a silica gel column (ethyl acetate:methanol=15:1 to ethyl acetate:methanol=5:1)
- customto obtain the specified substance in the form of a transparent oil at a yield of 0.049 g (yield: 91%)
Sources & evidence
- ORD record
- ord-a94626e9354046f094a755f1c2717309
- Source dataset
- uspto-grants-2011_10
- Patent number
- US08030438B2
Reaction notes
Loading…