Hydrochloric Acid → HCID 58967382, compound
Reaction equation
[NH2:1][C:2]1[CH:22]=[CH:21][CH:20]=[CH:19][C:3]=1[C:4]([NH:6][C@@H:7]([CH2:12][CH:13]1[CH2:18][CH2:17][CH2:16][CH2:15][CH2:14]1)[C:8]([O:10][CH3:11])=[O:9])=[O:5].Cl.[CH3:24]N1C(=O)CCC1>O1CCOCC1.O>[CH:13]1([CH2:12][C@H:7]([N:6]2[C:4](=[O:5])[C:3]3[C:2](=[CH:22][CH:21]=[CH:20][CH:19]=3)[N:1]=[CH:24]2)[C:8]([O:10][CH3:11])=[O:9])[CH2:14][CH2:15][CH2:16][CH2:17][CH2:18]1Participants
6
Reactant 3
Product 1
Reagents, catalysts & solvents 2
Conditions
- Temperature
- 100 °C
Procedure
To a solution of Compound 22 (1 g, 3.29 mmol) in 15 mL of NMP was added triethoxyorthformate (9.87 mmol), followed by 0.5 mL of 4M HCl in dioxane. The mixture was heated to 100° C. overnight, and then diluted with water and extracted with EtOAc. After removing the solvent, the residue was dissolved in MeOH and 7.9 mL of 2 M LiOH was added. The mixture was stirred for 4 hours and acidified with con. HCl to pH=4-5. The mixture was extracted with EtOAc and dried over MgSO4. Removing the solvent gave Compound 23. [M+H] calc'd for C17H20N2O3, 301; found, 301.
Workup
- extractionextracted with EtOAc
- customAfter removing the solvent
- dissolutionthe residue was dissolved in MeOH
- addition7.9 mL of 2 M LiOH was added
- extractionThe mixture was extracted with EtOAc
- dry with materialdried over MgSO4
- customRemoving the solvent
Sources & evidence
- ORD record
- ord-373ff20313c2417c809727300077cc3c
- Source dataset
- uspto-grants-2011_10
- Patent number
- US08034822B2
Reaction notes
Loading…