HRID1679503

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID962

Water

H2O

HCID8471

Triethylamine

C6H15N

HCID78890

1,3-Diethyl-2-thiobarbituric acid

C8H12N2O2S

结构：CCN1C(=CC#Cc2n(CC)c3nc4ccccc4nc3[n+]2CC)N(CC)c2nc3ccccc3nc21.[O-][Cl+3]([O-])([O-])[O-]

HCID86734798

未命名化合物

PRODUCTS

生成物

结构：CCN1C(=O)C(=C(C=C2N(CC)c3nc4ccccc4nc3N2CC)C=C2N(CC)c3nc4ccccc4nc3N2CC)C(=O)N(CC)C1=S

HCID20362965

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID6228

N,N-Dimethylformamide

C3H7NO

PROCEDURE

实验过程

A mixture of 1,3-diethyl-2-[(1,3-diethyl-1H-imidazo[4,5-b]quinoxalin-2-(3H)-ylidene)-1-propynyl]imidazo[4,5-b]quinoxalinium perchlorate) 0.33 g, 0.0005 mol) of Example 1, 1,3-diethyl-2-thiobarbituric acid (0.11 g, 0.0005 mol) and triethylamine (0.10 g, 0.001 mol) in dimethylformamide (5 ml), is heated at reflux for 30 seconds. After cooling the solution is diluted to 20 ml. with water. The dye is collected and washed with water. After recrystallization from acetonitrile, the yield of purified dye is 0.27 g (79%) - mp. indistinct.

WORKUP

后处理

temperatureis heated
temperatureat reflux for 30 seconds
temperatureAfter cooling the solution
additionis diluted to 20 ml
customThe dye is collected
washwashed with water
customAfter recrystallization from acetonitrile

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-f516f954c8934001a9087647f7007e25
来源数据集: uspto-grants-1978_03
DOI: 10.6084/m9.figshare.5104873.v1
专利: US04080496
来源说明: uspto-grants-1978_03

反应 SMILES

Cl([O-])(=O)(=O)=O.[CH2:6]([N+:8]1[C:12]2=[N:13][C:14]3[C:19]([N:20]=[C:11]2[N:10]([CH2:21][CH3:22])[C:9]=1[C:23]#[C:24][CH:25]=[C:26]1[N:38]([CH2:39][CH3:40])[C:29]2=[N:30][C:31]4[C:36]([N:37]=[C:28]2[N:27]1[CH2:41][CH3:42])=[CH:35][CH:34]=[CH:33][CH:32]=4)=[CH:18][CH:17]=[CH:16][CH:15]=3)[CH3:7].[CH2:43]([N:45]1[C:52](=[O:53])[CH2:51][C:49](=[O:50])[N:48]([CH2:54][CH3:55])[C:46]1=[S:47])[CH3:44].C(N(CC)CC)C.O>CN(C)C=O>[CH2:54]([N:48]1[C:49](=[O:50])[C:51](=[C:24]([CH:25]=[C:26]2[N:27]([CH2:41][CH3:42])[C:28]3=[N:37][C:36]4[C:31]([N:30]=[C:29]3[N:38]2[CH2:39][CH3:40])=[CH:32][CH:33]=[CH:34][CH:35]=4)[CH:23]=[C:9]2[N:10]([CH2:21][CH3:22])[C:11]3=[N:20][C:19]4[C:14]([N:13]=[C:12]3[N:8]2[CH2:6][CH3:7])=[CH:15][CH:16]=[CH:17][CH:18]=4)[C:52](=[O:53])[N:45]([CH2:43][CH3:44])[C:46]1=[S:47])[CH3:55]