Sodium hydride → 7-(3-Ethyl-4.5-diphenyl-2-oxo-4-imidazolin-1-yl) enanthic acid ethyl ester

HRID 1702882Notes

Reaction equation

HRID 1702882 reaction equation
[H-].[Na+].[CH2:3]([N:5]1[C:9]([C:10]2[CH:15]=[CH:14][CH:13]=[CH:12][CH:11]=2)=[C:8]([C:16]2[CH:21]=[CH:20][CH:19]=[CH:18][CH:17]=2)[NH:7][C:6]1=[O:22])[CH3:4].[CH2:23]([O:25][C:26](=[O:34])[CH2:27][CH2:28][CH2:29][CH2:30][CH2:31][CH2:32]Cl)[CH3:24]>CN(C=O)C>[CH2:23]([O:25][C:26](=[O:34])[CH2:27][CH2:28][CH2:29][CH2:30][CH2:31][CH2:32][N:7]1[C:8]([C:16]2[CH:21]=[CH:20][CH:19]=[CH:18][CH:17]=2)=[C:9]([C:10]2[CH:11]=[CH:12][CH:13]=[CH:14][CH:15]=2)[N:5]([CH2:3][CH3:4])[C:6]1=[O:22])[CH3:24]

Participants

5

Reactant 3

HCID 24758Sodium hydrideHCID 529988Ethyl 7-chloroheptanoateHCID 126751261-ethyl-4,5-diphenyl-1,3-dihydro-2H-imidazol-2-one

Product 1

HCID 537087157-(3-Ethyl-4.5-diphenyl-2-oxo-4-imidazolin-1-yl) enanthic acid ethyl ester

Reagents, catalysts & solvents 1

HCID 6228DimethylformamideSolvent

Procedure

The product is obtained as described in example 1 from 2.1 g of NaH (80% suspension in mineral oil), 18.5 g of 1-ethyl-4.5-diphenyl-4-imidazolin-2-one, 140 cc. of DMF, 13.5 g of 7-chloroenanthic acid ethyl ester and 2.1 g of NaJ.

Workup

  1. customThe product is obtained

Sources & evidence

ORD record
ord-5c9d7533d6a6403cad679228344b1a0a
Source dataset
uspto-grants-1982_09
Patent number
US04349684

Reaction notes

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