Hydrochloric Acid → 39640-04-5
Reaction equation
[N:1]1[CH:6]=[CH:5][C:4]([C:7]([N:9]2[CH2:14][CH2:13][N:12](C(OC(C)(C)C)=O)[CH2:11][CH2:10]2)=[O:8])=[CH:3][CH:2]=1.Cl.C([O-])([O-])=O.[K+].[K+]>C(Cl)Cl>[N:1]1[CH:6]=[CH:5][C:4]([C:7]([N:9]2[CH2:14][CH2:13][NH:12][CH2:11][CH2:10]2)=[O:8])=[CH:3][CH:2]=1Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
The title material was synthesized from the title product of Example 26 (1.3 g, 4.46 mmol) by the method described in Example 25, except that the title free base was generated by treatment of its HCl salt with 0.5N K2CO3 in CH2Cl2. The CH2Cl2 solution was dried over Na2SO4 and all solvent removed under reduced pressure to provide 333 mg of the title free base. This material was used without further purification.
Workup
- dry with materialThe CH2Cl2 solution was dried over Na2SO4
- customall solvent removed under reduced pressure
- customto provide 333 mg of the title free base
- customThis material was used without further purification
Sources & evidence
- ORD record
- ord-8f1c74933a8048a0a466d1baba5ba83c
- Source dataset
- uspto-grants-1994_10
- Patent number
- US05354747
Reaction notes
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