2-Fluoroethyl bromide → HCID 22235035, compound

HRID 1743582Notes

Reaction equation

HRID 1743582 reaction equation
[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([CH:8]([CH:10]([C:13]#[N:14])[C:11]#[N:12])[CH3:9])=[CH:4][CH:3]=1.[H-].[Na+].Br[CH2:18][CH2:19][F:20]>CN(C)C=O>[Cl:1][C:2]1[CH:3]=[CH:4][C:5]([CH:8]([C:10]([CH2:18][CH2:19][F:20])([C:11]#[N:12])[C:13]#[N:14])[CH3:9])=[CH:6][CH:7]=1

Participants

5

Reactant 3

HCID 129822-Fluoroethyl bromideHCID 24758Sodium hydrideHCID 11687105HCID 11687105, compound

Product 1

HCID 22235035HCID 22235035, compoundYield 44.6%

Reagents, catalysts & solvents 1

HCID 6228DimethylformamideSolvent

Procedure

Using 0.41 g of 2-(1-(4-chlorophenyl)ethyl)malononitrile, 5 ml of N,N-dimethylformamide, 0.12 g of sodium hydride (60% in oil), and 0.25 g of 1-bromo-2-fluoroethane, and according to the process described in the Production Example 1, there was obtained 0.22 g of 2-(1-(4-chlorophenyl)ethyl)-2-(2-fluoroethyl)malononitrile (the present compound (53)).

Sources & evidence

ORD record
ord-469fd4d2721443a580c9eb21d487b520
Source dataset
uspto-grants-2006_03
Patent number
US07011838B2

Reaction notes

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