2-Bromoethyl methyl ether → 2-Chloro-6-fluoro-4-(2-methoxy-ethoxy)-benzylalcohol

HRID 1794165Notes

Reaction equation

HRID 1794165 reaction equation
[Cl:1][C:2]1[CH:3]=[C:4]([OH:11])[CH:5]=[C:6]([F:10])[C:7]=1[CH2:8][OH:9].[CH3:12][O:13][CH2:14][CH2:15]Br>>[Cl:1][C:2]1[CH:3]=[C:4]([O:11][CH2:15][CH2:14][O:13][CH3:12])[CH:5]=[C:6]([F:10])[C:7]=1[CH2:8][OH:9]

Participants

3

Reactant 2

HCID 809722-Bromoethyl methyl etherHCID 222200093-Chloro-5-fluoro-4-(hydroxymethyl)phenol

Product 1

HCID 222200102-Chloro-6-fluoro-4-(2-methoxy-ethoxy)-benzylalcoholYield 52%

Procedure

This compound was prepared from 3-chloro-5-fluoro-4-hydroxymethyl-phenol and (2-bromoethyl) methyl ether according to the procedure described in Example 179 to give the product as a yellowish oil (209 mg, 52%); MS (EI): 234.1 (M)+.

Sources & evidence

ORD record
ord-006228abd25348f399201f56147c917e
Source dataset
uspto-grants-2006_04
Patent number
US07022707B2

Reaction notes

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