Sodium Iodide → HCID 16038370, compound
Reaction equation
[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([N:8]2[S:12](=[O:14])(=[O:13])[N:11]([CH:15]([C:19]3[CH:24]=[CH:23][CH:22]=[CH:21][CH:20]=3)[CH2:16][CH2:17]Cl)[C:10]3[CH:25]=[CH:26][CH:27]=[CH:28][C:9]2=3)=[CH:4][CH:3]=1.[I-].[Na+].[CH3:31][NH2:32]>>[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([N:8]2[C:9]3[CH:28]=[CH:27][CH:26]=[CH:25][C:10]=3[N:11]([C@@H:15]([C:19]3[CH:20]=[CH:21][CH:22]=[CH:23][CH:24]=3)[CH2:16][CH2:17][NH:32][CH3:31])[S:12]2(=[O:14])=[O:13])=[CH:4][CH:3]=1Participants
Procedure
1-(4-Chloro-phenyl)-3-(3-chloro-1-phenyl-propyl)-1,3-dihydro-benzo[1,2,5]-thiadiazole 2,2-dioxide (0.12 g) was dissolved in methylamine (8M in ethanol, 20 mL), sodium iodide (58 mg, 0.39 mmol) was added and the mixture stirred for 96 hours. The mixture was concentrated in vacuo and purified via chromatography (silica, 5% methanol saturated with ammonia in chloroform) to give (3R)-3-[3-(4-chlorophenyl)-2,2-dioxido-2,1,3-benzothiadiazol-1(3H)-yl]-N-methyl-3-phenylpropan-1-amine as a colorless oil. The freebase was dissolved in methanol (5 mL) and treated with 2N aqueous hydrochloric acid (1.0 equivalent) and concentrated. The residue was dissolved in water and lyophilized to give 130 mg (72%) (3R)-3-[3-(4-chlorophenyl)-2,2-dioxido-2,1,3-benzothiadiazol-1(3H)-yl]-N-methyl-3-phenylpropan-1-amine as hydrochloride salt as a white powder. MS (ES) m/z 427.8.
Workup
- concentrationThe mixture was concentrated in vacuo
- custompurified via chromatography (silica, 5% methanol saturated with ammonia in chloroform)
Sources & evidence
- ORD record
- ord-50701ce4ec8942e3afa1cfecaa09e2a1
- Source dataset
- uspto-grants-2009_10
- Patent number
- US07601744B2
Reaction notes
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