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HRID1861919

反应详情

EQUATION

反应方程式

HRID 1861919 的结构方程式

REACTANTS

反应物

2
结构：Cl
HCID313

Hydrochloric Acid

ClH

结构：CN(C)CCc1ccc([N+](=O)[O-])cc1
HCID220557

N,N-Dimethyl-2-(4-nitrophenyl)ethan-1-amine

C10H14N2O2

PRODUCTS

生成物

1
结构：CN(C)CCc1ccc(N)cc1.Cl.Cl
HCID53407838

4-[2-(Dimethylamino)ethyl]aniline--hydrogen chloride (1/2)

C10H18Cl2N2

收率 85%

AUXILIARIES

试剂、催化剂与溶剂

1
结构：C1COCCO1
溶剂HCID31275

1,4-Dioxane

C4H8O2

PROCEDURE

实验过程

Using the compound obtained in Example 97 as a starting material and after adding a solution of hydrogen chloride (4N) in 1,4-dioxane, the same procedure of Example 2 gave 2.37 g of the titled compound (yield, 85%).