Hydrochloric Acid → 6-(3-Phenylureido)nicotinic Acid
Reaction equation
[C:1]1([NH:7][C:8](=[O:20])[NH:9][C:10]2[CH:19]=[CH:18][C:13]([C:14]([O:16]C)=[O:15])=[CH:12][N:11]=2)[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.[OH-].[Li+].O.Cl>CO>[C:1]1([NH:7][C:8](=[O:20])[NH:9][C:10]2[CH:19]=[CH:18][C:13]([C:14]([OH:16])=[O:15])=[CH:12][N:11]=2)[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1Participants
6
Reactant 4
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 50 °C
Procedure
Methyl 6-(3-phenylureido)nicotinate (200 mg, 0.43 mmol) was dissolved in methanol (2 mL) at room temperature. Lithium hydroxide (100 mg, 4.17 mmol) was added, followed by water (10.5 mL). The mixture was heated to 50° C. and stirred overnight. The mixture was brought to pH 4-5 by addition of concentrated hydrochloric acid. The solid that had formed was then filtered and dried under vacuum to give the title compound (69 mg). MS (ESI) m/z 258.1[M+H]+
Workup
- customThe solid that had formed
- filtrationwas then filtered
- customdried under vacuum
Sources & evidence
- ORD record
- ord-fa63a2b679e444d189986a95767fecc5
- Source dataset
- uspto-grants-2012_11
- Patent number
- US08314091B2
Reaction notes
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