Hydrochloric Acid → 4-Iodophenol

HRID 1886119Notes

Reaction equation

Cl.Cl[Sn]Cl.[N+:5]([C:8]1[CH:13]=[C:12]([I:14])[CH:11]=[CH:10][C:9]=1[OH:15])([O-])=O>>[NH2:5][C:8]1[CH:13]=[C:12]([I:14])[CH:11]=[CH:10][C:9]=1[OH:15].[I:14][C:12]1[CH:13]=[CH:8][C:9]([OH:15])=[CH:10][CH:11]=1

Participants

Reactant 3

HCID 313Hydrochloric Acid

HCID 24479Stannous Chloride

HCID 179373Phenol, 4-iodo-2-nitro-

Product 2

HCID 108944-Iodophenol

HCID 145493972-Amino-4-iodophenol

Procedure

2-amino-4-iodophenol was prepared by the HCl and SnCl2 reduction of 2-nitro-4-iodophenol which was obtained from the nitration of p-iodophenol.

Sources & evidence

ORD record: ord-cdf73bef7de24b16b268ad1db7918cd3
Source dataset: uspto-grants-1992_09
DOI: 10.6084/m9.figshare.5104873.v1
Patent number: US05149755

Reaction notes

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