Triethylamine → HCID 12837108, compound
Reaction equation
[F:1][C:2]1[CH:3]=[C:4]([CH:8]=[CH:9][CH:10]=1)[C:5](Cl)=[O:6].C(N(CC)CC)C.[Cl:18][C:19]1[CH:20]=[CH:21][CH:22]=[C:23]([NH2:28])[C:24]=1[C:25]([OH:27])=[O:26]>C(Cl)Cl>[F:1][C:2]1[CH:3]=[C:4]([CH:8]=[CH:9][CH:10]=1)[C:5]([NH:28][C:23]1[C:24](=[C:19]([Cl:18])[CH:20]=[CH:21][CH:22]=1)[C:25]([OH:27])=[O:26])=[O:6]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
15.9 parts of 3-fluorobenzoyl chloride and 10.1 parts of triethylamine are introduced simultaneously, from 2 feeds, into a solution of 17.1 parts of 6-chloroanthranilic acid in 200 parts of methylene chloride at from 25° to 30° C. The reaction mixture is subsequently stirred for 30 minutes, and is extracted once with 1 N hydrochloric acid and then with water. The organic solution is dried and concentrated, giving 29 parts of N-(3'-fluorobenzoyl)-6-chloroanthranilic acid of melting point 216°-219° C.; yield: 98.6% of theory.
Workup
- extractionis extracted once with 1 N hydrochloric acid
- customThe organic solution is dried
- concentrationconcentrated
Sources & evidence
- ORD record
- ord-873c0ff91cca4625870dec5e59387f24
- Source dataset
- uspto-grants-1982_12
- Patent number
- US04363651
Reaction notes
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