Ethyl Acetate → 4-(2-Phenethyloxyethoxy)phenol
Reaction equation
C([O:8][C:9]1[CH:14]=[CH:13][C:12]([O:15][CH2:16][CH2:17][O:18][CH2:19][CH2:20][C:21]2[CH:26]=[CH:25][CH:24]=[CH:23][CH:22]=2)=[CH:11][CH:10]=1)C1C=CC=CC=1.C(OCC)(=O)C>C(O)C.[Pd]>[CH2:19]([O:18][CH2:17][CH2:16][O:15][C:12]1[CH:13]=[CH:14][C:9]([OH:8])=[CH:10][CH:11]=1)[CH2:20][C:21]1[CH:22]=[CH:23][CH:24]=[CH:25][CH:26]=1Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
The 1-benzyloxy-4-(2-phenethyloxyethoxy)benzene obtained according to the preceding paragraph was dissolved in 200 ml of ethanol and 200 ml of ethyl acetate and hydrogenated overnight at atmospheric pressure and room temperature in the presence of 0.4 g of 10% palladium/carbon. The catalyst was removed by filtration and the filtrate was evaporated to give 10.8 g (91%) of 4-(2-phenethyloxyethoxy)phenol in the form of an oil which was homogeneous according to chromatography.
Workup
- customat atmospheric pressure and room temperature
- customThe catalyst was removed by filtration
- customthe filtrate was evaporated
Sources & evidence
- ORD record
- ord-0e006ecf2e0540c9b023e26ed794f5cc
- Source dataset
- uspto-grants-1987_03
- Patent number
- US04649160
Reaction notes
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