Iodoethane → 9-Ethyl-9H-fluorene
Reaction equation
[CH:1]1[C:13]2[CH2:12][C:11]3[C:6](=[CH:7][CH:8]=[CH:9][CH:10]=3)[C:5]=2[CH:4]=[CH:3][CH:2]=1.[Li][CH2:15][CH2:16]CC.ICC>>[CH2:15]([CH:12]1[C:11]2[CH:10]=[CH:9][CH:8]=[CH:7][C:6]=2[C:5]2[C:13]1=[CH:1][CH:2]=[CH:3][CH:4]=2)[CH3:16]Participants
4
Procedure
Fluorene (5.0 g, 30.1 mmol), n-BuLi (16 ml, 40 mmol, 2.5 M in hexane), RX=iodoethane (7.04 g, 45.1 mmol). 41 was isolated as yellow oil (5.7 g, 97%).
Sources & evidence
- ORD record
- ord-4d031c84ab044a2f9c5a75a678f3a061
- Source dataset
- uspto-grants-2013_12
- Patent number
- US08618328B2
Reaction notes
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