4-Fluoro-2-methyl-6-nitroaniline → HCID 23297976, compound
Reaction equation
[F:1][C:2]1[CH:8]=[C:7]([N+:9]([O-])=O)[C:5]([NH2:6])=[C:4]([CH3:12])[CH:3]=1>O1CCCC1.[Ni]>[NH2:6][C:5]1[C:7]([NH2:9])=[CH:8][C:2]([F:1])=[CH:3][C:4]=1[CH3:12]Participants
4
Reactant 1
Product 1
Reagents, catalysts & solvents 2
Procedure
25 g (0.147 mol) of 4-fluoro-2-methyl-6-nitroaniline in 250 ml of tetrahydrofuran are hydrogenated at about 34° C. for 2 hours in the presence of 8 g of Raney nickel. The reaction mixture is then filtered off and concentrated. The title compound is obtained as a brown oil.
Workup
- filtrationThe reaction mixture is then filtered off
- concentrationconcentrated
Sources & evidence
- ORD record
- ord-6a9a47c2f2b24015a1fcf9fa351f4736
- Source dataset
- uspto-grants-2000_09
- Patent number
- US06117873
Reaction notes
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