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HRID1962454

反应详情

EQUATION

反应方程式

HRID 1962454 的结构方程式

REACTANTS

反应物

3
结构：CN(C(=O)OC(C)(C)C)C1CCNC1
HCID2761404

tert-Butyl methyl(pyrrolidin-3-yl)carbamate

C10H20N2O2

结构：CN(C(=O)OC(C)(C)C)[C@H]1CCNC1
HCID7171888

tert-Butyl methyl[(3S)-pyrrolidin-3-yl]carbamate

C10H20N2O2

结构：CN(C(=O)OC(C)(C)C)C1CCN(S(=O)(=O)c2cccc3c(Cl)ncc(Br)c23)C1
HCID87322379

未命名化合物

2 次

PRODUCTS

生成物

2
结构：Cl
HCID313

Hydrochloric Acid

ClH

结构：CNC1CCN(S(=O)(=O)c2cccc3c(O)ncc(Br)c23)C1
HCID178482263

未命名化合物

PROCEDURE

实验过程

3-[N-(tert-Butoxycarbonyl)-N-methylamino]-1-(1-chloro-4-bromo-5-isoquinolinesulfonyl)pyrrolidine (Intermediate 24) can be prepared by using 3-[N-(tert-butoxycarbonyl)-N-methylamino]pyrrolidine in the method of Example 35-1, Step A instead of (S)-3-[N-(tert-butoxycarbonyl)-N-methylamino]pyrrolidine, and then used in the method of Example 35-1, Step Bin a similar manner to obtain the title compound as hydrochloride.