Hydrochloric Acid → HCID 69954724, compound
Reaction equation
[NH2:1][C:2]1[N:3]2[C:14]([C:15]3[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=3)=[CH:13][N:12]([N:21]3[C:30](=[O:31])[C:29]4[C:24](=[CH:25][C:26]([C:32]([O:34]C)=[O:33])=[CH:27][CH:28]=4)[N:23]=[C:22]3[CH3:36])[C:11](=[O:37])[C:5]3=[CH:6][CH2:7][CH2:8][C:9]([CH:10]=1)=[C:4]23.C1COCC1.[OH-].[K+].Cl>O.C(Cl)Cl.CO>[NH2:1][C:2]1[N:3]2[C:14]([C:15]3[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=3)=[CH:13][N:12]([N:21]3[C:30](=[O:31])[C:29]4[C:24](=[CH:25][C:26]([C:32]([OH:34])=[O:33])=[CH:27][CH:28]=4)[N:23]=[C:22]3[CH3:36])[C:11](=[O:37])[C:5]3=[CH:6][CH2:7][CH2:8][C:9]([CH:10]=1)=[C:4]23Participants
7
Conditions
- Temperature
- 22.5 °C
Procedure
0.6 g (1.22 mmmol) of the product of Example 28A and 30 ml of THF are introduced into a reactor. After solubilization, a solution of 0.135 g of KOH in 8 ml of water is added and the mixture is kept stirring for 3 h at 20-25° C. The mixture is neutralized with 0.1 N HCl to pH 6.8 and the THF is evaporated off at 50° C. under a vacuum of 20 rnm Hg. The residue is chromatographed, eluting with CH2Cl2 progressively enriched with methanol. The product obtained is crystallized from 10 ml of CH2Cl2 and the precipitate is filtered off. 0.25 g is obtained (Yld=42.7%). M.p.>275° C.—TLC (85/15 CH2Cl2/MeOH): Rf=0.35.
Workup
- customthe THF is evaporated off at 50° C. under a vacuum of 20 rnm Hg
- customThe residue is chromatographed
- washeluting with CH2Cl2
- customThe product obtained
- customis crystallized from 10 ml of CH2Cl2
- filtrationthe precipitate is filtered off
- custom0.25 g is obtained (Yld=42.7%)
Sources & evidence
- ORD record
- ord-78618c1aa24641c28410d2dd7159f590
- Source dataset
- uspto-grants-2001_05
- Patent number
- US06239130B1
Reaction notes
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