HRID2040782

反应详情

EQUATION

反应方程式

HRID 2040782 的结构方程式

PROCEDURE

实验过程

A solution of 2-(1-ethyl-propyl)-6-methyl-isonicotinic acid isopropyl ester (1.54 g, 6.18 mmol) in 25% aq. HCl (60 mL) is stirred at 65° C. for 16 h. The solvent is removed in vacuo and the residue is dissolved in dioxane and concentrated again to give 2-(1-ethyl-propyl)-6-methyl-isonicotinic acid hydrochloride (1.70 g) as a brownish solid; LC-MS: tR=0.62 min, [M+1]+=208.52.

WORKUP

后处理

  1. customThe solvent is removed in vacuo
  2. dissolutionthe residue is dissolved in dioxane
  3. concentrationconcentrated again