Potassium Carbonate → (R,R)-Stilbene oxide

HRID 2119937Notes

Reaction equation

HRID 2119937 reaction equation
[C:1]1(/[CH:7]=[CH:8]/[C:9]2[CH:14]=[CH:13][CH:12]=[CH:11][CH:10]=2)[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.[OH:15]OS([O-])=O.[K+].C([O-])([O-])=O.[K+].[K+]>C(#N)C.C(N(CC([O-])=O)CC(O)=O)CN(CC([O-])=O)CC(O)=O.[Na+].[Na+].S([O-])(O)(=O)=O.C([N+](CCCC)(CCCC)CCCC)CCC.O>[CH:4]1[CH:3]=[CH:2][C:1]([C@H:7]2[O:15][C@@H:8]2[C:9]2[CH:10]=[CH:11][CH:12]=[CH:13][CH:14]=2)=[CH:6][CH:5]=1

Participants

8

Reactant 3

HCID 11430Potassium CarbonateHCID 638088trans-StilbeneHCID 23707502Potassium hydroxy sulfite

Product 1

HCID 185583(R,R)-Stilbene oxideYield 85%

Reagents, catalysts & solvents 4

HCID 94433Tetrabutylammonium hydrogen sulfateCatalystHCID 962WaterSolventHCID 6342AcetonitrileSolventHCID 8759EDTA disodium saltSolvent2×

Procedure

Reaction at 20° C.: trans-Stilbene (0.181 g, 1 mmol) was dissolved in acetonitrile/DMM (15 mL, ½, V/V). subsequently were added buffer (10 mL, 0.05 M solution of Na2B4O7.H2O in 4×10−4 M aqueous Na2EDTA), tetrabutylammonium hydrogen sulfate (0.015 g, 0.04 mmol), and ketone 1 (0.0774 g, 0.3 mmol). A solution of Oxone® (1.0 g, 1.6 mmol) in aqueous Na2EDTA (4×10−4 M, 6.5 mL) and a solution of K2CO3 (0.93 g, 6.74 mmol) in water (6.5 mL) were added dropwise separately over a period of 30 min (via additional funnels). The reaction was then worked up by the same procedure as Method A to afford trans-stilbene oxide (0.166 g, 85% yield, 97.9% ee).

Workup

  1. customReaction at 20° C.

Sources & evidence

ORD record
ord-daaa5bbbc0ef4fb4bbdd9c84dc72f292
Source dataset
uspto-grants-2004_02
Patent number
US06686483B2

Reaction notes

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