HRID2152435

反应详情

EQUATION

反应方程式

HRID 2152435 的结构方程式

REACTANTS

反应物

4

结构：ClCCl

Dichloromethane

CH2Cl2

结构：CCN(CC)CC

Triethylamine

C6H15N

结构：O=S(=O)(OS(=O)(=O)C(F)(F)F)C(F)(F)F

Trifluoromethanesulfonic anhydride

C2F6O5S2

结构：Cc1c(O)c([N+](=O)[O-])c2n(c1=O)CCO2

7-Hydroxy-6-methyl-8-nitro-2,3-dihydro-5H-[1,3]oxazolo[3,2-a]pyridin-5-one

C8H8N2O5

PRODUCTS

生成物

1

结构：Cc1c(OS(=O)(=O)C(F)(F)F)c([N+](=O)[O-])c2n(c1=O)CCO2

Methanesulfonic acid, 1,1,1-trifluoro-, 2,3-dihydro-6-methyl-8-nitro-5-oxo-5H-oxazolo[3,2-a]pyridin-7-yl ester

C9H7F3N2O7S