Trifluoroacetic acid → 5,6-Dihydrophenanthridine
Reaction equation
[CH2:1]([C:3]1[N:4]=[C:5]2[C:10](=[C:11]3[C:16]=1[CH:15]=[C:14]([F:17])[CH:13]=[CH:12]3)[CH:9]=[CH:8][CH:7]=[CH:6]2)[CH3:2].[BH4-].[Na+].FC(F)(F)C(O)=O.C1C=CC2C3C=CC=CC=3NCC=2C=1.C(N(CC)CC)C.[Cl:48][C:49]1[CH:50]=[C:51]([S:57](Cl)(=[O:59])=[O:58])[CH:52]=[CH:53][C:54]=1[O:55][CH3:56]>O1CCCC1.ClCCl>[CH:14]1[CH:13]=[CH:12][C:11]2[C:10]3[CH:9]=[CH:8][CH:7]=[CH:6][C:5]=3[NH:4][CH2:3][C:16]=2[CH:15]=1.[CH2:1]([CH:3]1[C:16]2[C:11](=[CH:12][CH:13]=[C:14]([F:17])[CH:15]=2)[C:10]2[CH:9]=[CH:8][CH:7]=[CH:6][C:5]=2[N:4]1[S:57]([C:51]1[CH:52]=[CH:53][C:54]([O:55][CH3:56])=[C:49]([Cl:48])[CH:50]=1)(=[O:58])=[O:59])[CH3:2]Participants
10
Reactant 6
Product 2
Reagents, catalysts & solvents 2
Procedure
The intermediate dihydrophenanthridine was prepared from 6-ethyl-8-fluorophenanthridine, (Example 40, Step b, 0.40 g, 1.8 mmol), by treatment with sodium borohydride (0.40 g, 10.6 mmol) and trifluoroacetic acid (0.55 mL, 7.1 mmol) in tetrahydrofuran (7 mL). In a separate, second step, the dihydrophenanthridine was treated with triethylamine (0.9 mL, 6.4 mmol) and 3-chloro-4-methoxybenzenesulfonyl chloride (0.51 g, 2.1 mmol, 2.1 equivalents) in dichloromethane (5 mL), according to the procedure and in the same manner as described in Example 32, Method A, Step d, to afford 6-ethyl-8-fluoro-5-[(3-chloro-4-methoxyphenyl)sulfonyl]-5,6-dihydrophenanthridine as a crude product, which was utilized without further purification.
Sources & evidence
- ORD record
- ord-1afc60d4b4184dada63199b24b44fd26
- Source dataset
- uspto-grants-2005_05
- Patent number
- US06894061B2
Reaction notes
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