HRID2183482

反应详情

EQUATION

反应方程式

HRID 2183482 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

CONDITIONS

反应条件

温度
70 °C

PROCEDURE

实验过程

To a solution of compound 16A (31 mg, 0.09 mmol) in 1:1 MeOH:CH2Cl2 (2 mL) was added NaHCO3 (30 mg, 0.36 mmol). The reaction was kept at room temperature for 3 h, heated to 70° C. for 1 h, cooled to room temperature, concentrated to dryness, redissolved in CH2Cl2 and filtered. The filtrate was concentrated to give compound 17A as a yellow solid (26 mg, 98%).

WORKUP

后处理

  1. temperaturecooled to room temperature
  2. concentrationconcentrated to dryness
  3. dissolutionredissolved in CH2Cl2
  4. filtrationfiltered
  5. concentrationThe filtrate was concentrated