HRID2197738

反应详情

EQUATION

反应方程式

HRID 2197738 的结构方程式

PROCEDURE

实验过程

The product from Example 2a 1.0 g, 5.37 mmol) was reacted with propyl iodide 0.55 mL, 5.64 mmol) in place of ethyl iodide following the procedure from Example 2b to give the title compound (790 mg, 64%).