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HRID22075

反应详情

EQUATION

反应方程式

HRID 22075 的结构方程式

REACTANTS

反应物

4
结构：CCN(C(C)C)C(C)C
HCID81531

Diisopropylethylamine

C8H19N

结构：CC(C)(C)[Si](C)(C)OS(=O)(=O)C(F)(F)F
HCID123564

tert-Butyldimethylsilyl trifluoromethanesulphonate

C7H15F3O3SSi

结构：CCC[C@@H]1O[C@]1(C)CO
HCID10931464

未命名化合物

结构：CCC[C@@H](O[Si](C)(C)C(C)(C)C)[C@@H](C)C=O
HCID14959487

未命名化合物

PRODUCTS

生成物

1
结构：CCC[C@H](O[Si](C)(C)C(C)(C)C)[C@H](C)C=O
HCID10879364

未命名化合物

PROCEDURE

实验过程

Epoxy alcohol 13, 1.25 eq TBSOTf, and 1.30 eq DIPEA were reacted as in the preparation of 16 to give the crude aldehyde 14 in 95% +yield. 1H NMR, 13C NMR, IR, and high resolution MS are identical to 16. [δ]D=+19.3° (c=1.10, CH2Cl2). 1H NMR integration of δ 9.67 and the contaminating diastereromer at δ 9.71 indicated a >50:1 ratio.