1-Propanol → HCID 15180132, compound

HRID 2248643Notes

Reaction equation

HRID 2248643 reaction equation
[Na].Cl[C:3]1[C:4]([C:8]2[CH:9]=[N:10][CH:11]=[CH:12][CH:13]=2)=[N:5][S:6][N:7]=1.[CH2:14]([OH:17])[CH2:15][CH3:16]>>[CH2:14]([O:17][C:3]1[C:4]([C:8]2[CH:9]=[N:10][CH:11]=[CH:12][CH:13]=2)=[N:5][S:6][N:7]=1)[CH2:15][CH3:16]

Participants

4

Reactant 3

HCID 10311-PropanolHCID 5360545SodiumHCID 104881643-Chloro-4-(pyridin-3-yl)-1,2,5-thiadiazole

Product 1

HCID 15180132HCID 15180132, compoundYield 96%

Conditions

Temperature
50 °C

Procedure

To a solution of sodium (440 mg, 17 mmol) in 1-propanol (10 ml) was added 3-(4-chloro-1,2,5-thiadiazol-3-yl)pyridine (650 mg, 3.3 mmol). The mixture was stirred at 50° C. for 2 h and evaporated. The residue was dissolved in water and extracted with methylene chloride. The combined organic phases were dried and evaporated to yield 700 mg (96%) of the title compound.

Workup

  1. customevaporated
  2. dissolutionThe residue was dissolved in water
  3. extractionextracted with methylene chloride
  4. customThe combined organic phases were dried
  5. customevaporated

Sources & evidence

ORD record
ord-97014fe319b14d758bf392c1e22519f9
Source dataset
uspto-grants-1991_08
Patent number
US05041455

Reaction notes

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