Hydrogen Peroxide → Benzophenone
Reaction equation
[Br-].[Na+].[C:3]1([CH2:9][C:10]2[CH:15]=[CH:14][CH:13]=[CH:12][CH:11]=2)[CH:8]=[CH:7][CH:6]=[CH:5][CH:4]=1.[OH:16]O>O.O.O.O.C([O-])(=O)C.[Co+2].C([O-])(=O)C>[C:9]([C:10]1[CH:11]=[CH:12][CH:13]=[CH:14][CH:15]=1)(=[O:16])[C:3]1[CH:8]=[CH:7][CH:6]=[CH:5][CH:4]=1Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
The procedure of Example I was repeated, but this time cobalt (II) acetate tetrahydrate (0.008 moles), sodium bromide (0.04 moles), diphenylmethane (0.055 moles) and hydrogen peroxide (35%, 0.28 moles) were used. The final reaction mixture, analysed by HPLC, revealed that 91.5% of the diphenylmethane had been consumed, yielding products including benzophenone (72.3% yield).
Workup
- customThe final reaction mixture
- customhad been consumed
- customyielding products
Sources & evidence
- ORD record
- ord-d6afbf3d53ec4c119de8b47e14dbae74
- Source dataset
- uspto-grants-1995_12
- Patent number
- US05473101
Reaction notes
Loading…