Potassium Iodide → HCID 59596828, compound
Reaction equation
Cl[CH2:2][C:3]1[CH:8]=[CH:7][CH:6]=[C:5]([F:9])[CH:4]=1.[C:10]([O:14][C:15](=[O:26])[NH:16][CH2:17][CH2:18][C:19]1[CH:24]=[CH:23][CH:22]=[C:21]([OH:25])[CH:20]=1)([CH3:13])([CH3:12])[CH3:11].C([O-])([O-])=O.[K+].[K+].[I-].[K+]>CN(C)C=O>[C:10]([O:14][C:15](=[O:26])[NH:16][CH2:17][CH2:18][C:19]1[CH:24]=[CH:23][CH:22]=[C:21]([O:25][CH2:2][C:3]2[CH:8]=[CH:7][CH:6]=[C:5]([F:9])[CH:4]=2)[CH:20]=1)([CH3:13])([CH3:11])[CH3:12]Participants
6
Procedure
2.87 g (19.8 mmol) of 1-chloromethyl-3-fluoro-benzene in 5 ml of dry dimethylformamide were added to a suspension of 4.66 g (19.6 mmol) of [2-(3-hydroxy-phenyl)-ethyl]-carbamic acid tert-butyl ester, 4 g of K2CO3 and 0.3 g of potassium iodide in 50 ml of dry dimethylformamide. The reaction was first stirred at room temperature overnight, then was heated up to 50° C. for 6 hours. After evaporation of the solvent, water was added to the residue and the product was extracted with ethyl acetate. 7 g of crude oil were obtained. Purification by flash chromatography using a mixture of ethyl acetate/hexane (1:9→2:8 gradient) gave 5.9 g (86% yield) of the title product as a colourless oil.
Workup
- temperaturewas heated up to 50° C. for 6 hours
- customAfter evaporation of the solvent, water
- additionwas added to the residue
- extractionthe product was extracted with ethyl acetate
- custom7 g of crude oil were obtained
- customPurification by flash chromatography
- additiona mixture of ethyl acetate/hexane (1:9→2:8 gradient)
Sources & evidence
- ORD record
- ord-ab71620d230a4988915e4a34e0ab3a20
- Source dataset
- uspto-grants-2010_12
- Patent number
- US07855227B2
Reaction notes
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