1-Chloro-4-nitrobenzene → HCID 972080, compound

HRID 2292259Notes

Reaction equation

HRID 2292259 reaction equation
Cl[C:2]1[CH:7]=[CH:6][C:5]([N+:8]([O-:10])=[O:9])=[CH:4][CH:3]=1.[F:11][C:12]1[CH:13]=[C:14]([OH:18])[CH:15]=[CH:16][CH:17]=1.[H-].[Na+]>O1CCCC1>[N+:8]([C:5]1[CH:6]=[CH:7][C:2]([O:18][C:14]2[CH:13]=[C:12]([F:11])[CH:17]=[CH:16][CH:15]=2)=[CH:3][CH:4]=1)([O-:10])=[O:9]

Participants

5

Reactant 3

HCID 74741-Chloro-4-nitrobenzeneHCID 97433-FluorophenolHCID 24758Sodium hydride

Product 1

HCID 972080HCID 972080, compound

Reagents, catalysts & solvents 1

HCID 8028TetrahydrofuranSolvent

Procedure

p-chloro-nitrobenzene and m-fluoro-phenol in tetra-hydrofuran in the presence of sodium hydride were reacted to obtain 3-(4-nitrophenoxy)-fluorobenzene which was nitrated to form 4-nitro-3-(4-nitrophenoxy)-fluorobenzene which was reacted as in Example 1 to obtain 0-[4-nitro-3-(4-nitrophenoxy)-phenyl]-hydroxylamine melting at 132° C.

Sources & evidence

ORD record
ord-da9608ccfeec422cb9ba9bf864201480
Source dataset
uspto-grants-1989_01
Patent number
US04801717

Reaction notes

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