Nitric Acid → Ethyl 2-bromo-4-fluoro-5-nitrobenzyl ether
Reaction equation
[Br:1][C:2]1[CH:11]=[C:10]([F:12])[CH:9]=[CH:8][C:3]=1[CH2:4][O:5][CH2:6][CH3:7].[N+:13]([O-])([OH:15])=[O:14].S(=O)(=O)(O)O>ClCCCl>[Br:1][C:2]1[CH:11]=[C:10]([F:12])[C:9]([N+:13]([O-:15])=[O:14])=[CH:8][C:3]=1[CH2:4][O:5][CH2:6][CH3:7]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
By the method of Example 2, Step D, 7.18 g (0.0308 mole) of ethyl 2-bromo-4-fluoro benzyl ether, 2 ml of fuming nitric acid, and 18 ml of concentrated sulfuric acid were reacted in 20 ml of 1,2-dichloroethane, yielding 3.1 g of ethyl 2-bromo-4-fluoro-5-nitrobenzyl ether.
Sources & evidence
- ORD record
- ord-0e3831de4bf74c01a4a48d3bd575b357
- Source dataset
- uspto-grants-1989_07
- Patent number
- US04846882
Reaction notes
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