3-Iodo-1-propanol → HCID 69481032, compound

HRID 2364371Notes

Reaction equation

HRID 2364371 reaction equation
[F:1][C:2]1[CH:7]=[CH:6][C:5]([CH2:8][C:9]2[CH:18]=[C:17]3[C:12]([C:13]([OH:25])=[C:14]([C:20]([O:22][CH2:23][CH3:24])=[O:21])[C:15](=[O:19])[NH:16]3)=[N:11][CH:10]=2)=[CH:4][CH:3]=1.I[CH2:27][CH2:28][CH2:29][OH:30]>O1CCCC1>[F:1][C:2]1[CH:7]=[CH:6][C:5]([CH2:8][C:9]2[CH:18]=[C:17]3[C:12]([C:13]([OH:25])=[C:14]([C:20]([O:22][CH2:23][CH3:24])=[O:21])[C:15](=[O:19])[N:16]3[CH2:27][CH2:28][CH2:29][OH:30])=[N:11][CH:10]=2)=[CH:4][CH:3]=1

Participants

4

Reactant 2

HCID 693903-Iodo-1-propanolHCID 54729997Ethyl 7-[(4-Fluorophenyl)methyl]-4-hydroxy-2-oxo-1,2-dihydro-1,5-naphthyridine-3-carboxylate

Product 1

HCID 69481032HCID 69481032, compoundYield 95%

Reagents, catalysts & solvents 1

HCID 8028TetrahydrofuranSolvent

Procedure

In a similar manner to that described in example 316 step 1, from ethyl 7-[(4-fluorophenyl)methyl]-4-hydroxy-2-oxo-1,2-dihydro-1,5-naphthyridine-3-carboxylate (20 mg, 0.0584 mmol), lithium (bis-trimethylsilyl)amide (0.18 mL of a 1 M tetrahydrofuran solution, 0.18 mmol), and 3-iodo-1-propanol (0.03 mL, 0.350 mmol) was prepared ethyl 7-[(4-fluorophenyl)methyl]-4-hydroxy-1-(3-hydroxypropyl)-2-oxo-1,2-dihydro-1,5-naphthyridine-3-carboxylate (22 mg, 95% yield) as a yellow oil. The product was carried on without further purification. MS m/z 423 (M+23).

Sources & evidence

ORD record
ord-07534e1a2dca4e819687c51def2feae4
Source dataset
uspto-grants-2014_04
Patent number
US08691991B2

Reaction notes

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