Fluorine → Trifluoromethanesulfonic anhydride
Reaction equation
[F:1][C:2]([F:8])([F:7])[S:3]([OH:6])(=[O:5])=[O:4].[P].FF>>[F:1][C:2]([F:8])([F:7])[S:3]([O:6][S:3]([C:2]([F:8])([F:7])[F:1])(=[O:5])=[O:4])(=[O:5])=[O:4]Participants
4
Procedure
Then, the first distillation of Example 1 was repeated, thereby to obtain 363.8 kg of trifluoromethanesulfonic acid anhydride which is colorless and transparent. By chemical analysis, this first distillate was found to have a purity of 97 wt % and contain 2 wt % of trifluoromethanesulfonic acid ester, 1 wt % of trifluoromethanesulfonic acid, up to 5 wt ppm of phosphorus, and 2,440 wt ppm of free fluorine. The actual amount of trifluoromethanesulfonic acid anhydride produced by the reaction was 32.9 kg, and the yield was 70%, based on the amount of trifluoromethanesulfonic acid.
Sources & evidence
- ORD record
- ord-ce8307b9a49e4d1897e32b6c226bddb7
- Source dataset
- uspto-grants-1998_09
- Patent number
- US05808149
Reaction notes
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