Hydrochloric Acid → (3-BROMOBENZYL)DIMETHYLAMINE
Reaction equation
[CH3:1][NH:2][CH3:3].[Br:4][C:5]1[CH:6]=[C:7]([CH:10]=[CH:11][CH:12]=1)[CH2:8]Br.Cl>C1C=CC=CC=1>[Br:4][C:5]1[CH:6]=[C:7]([CH:10]=[CH:11][CH:12]=1)[CH2:8][N:2]([CH3:3])[CH3:1]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
Dimethylamine (51.4 g, 1.14 mol) was reacted with 3-bromobenzyl bromide (95 g, 0.38 mol) in benzene at 5° and the mixtue was acidified with hydrochloric acid and the mixture was extracted with aqueous 3N hydrochloric acid. The aqueous extracts were made alkaline with aqueous potassium hydroxide and the oil which separated out was distilled to give 3-bromo-N,N-dimethylbenzylamine (65 g, 80%) b.p. 118°/20 mmHg.
Workup
- extractionthe mixture was extracted with aqueous 3N hydrochloric acid
- customthe oil which separated out
- distillationwas distilled
Sources & evidence
- ORD record
- ord-52b2dd3f106e4e15a3e588899cbbad87
- Source dataset
- uspto-grants-1985_01
- Patent number
- US04496567
Reaction notes
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