Hydrochloric Acid → HCID 20313022, compound
Reaction equation
C[O:2][C:3]1[CH:20]=[CH:19][C:6]([CH2:7][C:8]2[CH:9]=[CH:10][C:11]([C:14]([O:16][CH2:17][CH3:18])=[O:15])=[N:12][CH:13]=2)=[CH:5][CH:4]=1.Cl>C(O)C>[OH:2][C:3]1[CH:20]=[CH:19][C:6]([CH2:7][C:8]2[CH:9]=[CH:10][C:11]([C:14]([O:16][CH2:17][CH3:18])=[O:15])=[N:12][CH:13]=2)=[CH:5][CH:4]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 120 °C
Procedure
One gram of ethyl 5-(4-methoxybenzyl)picolinate was dissolved in 20 ml. of ethyl alcohol saturated with hydrochloric acid. The solution was heated in a sealed tube at 120° C. for 24 hours. The solvent was distilled out and the residue was added with cold water. Crystals thus formed were collected by filtration and recrystallized from ethyl acetate to obtain 0.8 g of ethyl 5-(4-hydroxybenzyl)-picolinate as colorless needle-like crystals of a melting point of 153°~156° C.
Workup
- distillationThe solvent was distilled out
- additionthe residue was added with cold water
- customCrystals thus formed
- filtrationwere collected by filtration
- customrecrystallized from ethyl acetate
Sources & evidence
- ORD record
- ord-60dd8a19a58e4a8c855778cadaacfd9c
- Source dataset
- uspto-grants-1978_08
- Patent number
- US04109000
Reaction notes
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