Hydrochloric Acid → (3-Butoxy-4-iodophenyl)methanol

HRID 250918Notes

Reaction equation

HRID 250918 reaction equation
[BH4-].[Li+].[CH2:3]([O:7][C:8]1[CH:9]=[C:10]([CH:15]=[CH:16][C:17]=1[I:18])[C:11](OC)=[O:12])[CH2:4][CH2:5][CH3:6].Cl>O1CCCC1>[CH2:3]([O:7][C:8]1[CH:9]=[C:10]([CH2:11][OH:12])[CH:15]=[CH:16][C:17]=1[I:18])[CH2:4][CH2:5][CH3:6]

Participants

5

Conditions

Temperature
60 °C

Procedure

8.17 g (0.375 mol, 3 eq) of lithium borohydride are added to a solution of 41.78 g (0.125 mol, 1 eq) of methyl 3-butoxy-4-iodobenzoate in 210 ml of tetrahydrofuran. The reaction medium is heated at 60° C. for 2 hours and then hydrolyzed cautiously in ice-cold saturated ammonium chloride solution. The reaction medium is neutralized with concentrated hydrochloric acid and then extracted with ethyl acetate. The organic phases are washed with water and dried over magnesium sulfate. The solvent is evaporated off and 38.31 g of (3-butoxy-4-iodophenyl)methanol are obtained in the form of a whitish oil. Yield=100%

Workup

  1. extractionextracted with ethyl acetate
  2. washThe organic phases are washed with water
  3. dry with materialdried over magnesium sulfate
  4. customThe solvent is evaporated off

Sources & evidence

ORD record
ord-eee1ad85d61548aca610dd90d3bf67b0
Source dataset
uspto-grants-2011_01
Patent number
US07863332B2

Reaction notes

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