Ethyl Acetate → 1-Bromo-7-phenylheptane

HRID 324100Notes

Reaction equation

HRID 324100 reaction equation
[C:1]1([CH2:7][CH2:8][CH2:9][CH2:10][CH2:11][CH2:12][CH2:13]O)[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.C(Br)(Br)(Br)[Br:16].C1(P(C2C=CC=CC=2)C2C=CC=CC=2)C=CC=CC=1.CCOC(C)=O>C(Cl)Cl>[Br:16][CH2:13][CH2:12][CH2:11][CH2:10][CH2:9][CH2:8][CH2:7][C:1]1[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1

Participants

6

Reactant 4

HCID 8857Ethyl AcetateHCID 11205Carbon tetrabromideHCID 11776TriphenylphosphineHCID 154271Benzeneheptanol

Product 1

HCID 27356031-Bromo-7-phenylheptaneYield 147.6%

Reagents, catalysts & solvents 1

HCID 6344DichloromethaneSolvent

Procedure

To a solution of 7-phenyl-1-heptanol (29.1 g, 151.3 mmol) in 800 mL CH2Cl2 at room temperature was added CBr4 (60.2 g, 181.6 mmol) then triphenylphosphine (47.6 g, 181.6 mmol). After 30 s, the reaction had turned a light green color. TLC indicated that the reaction was complete at this point. The solvent was removed in vacuo to give a greenish-white semisolid. To this material was added 10% EtOAc:90% Hexanes and the resulting suspension was filtered through a pad of silica gel washing well with the same solvent system. There yielded 57 g of a colorless oil as the desired bromide and triphenylphosphine oxide. This oil was then flash chromatographed (Hexanes) to yield 38.6 g, 100% of the bromide as a colorless oil. 1H NMR (CDCl3) δ1.30-1.49 (m, 6H); 1.60 (quintet, J=8.18 Hz, 2H); 2.60 (t, J=8.18 Hz, 2H); 3.39 (t, J=8.18 Hz, 2H); 7.13-7.20 (m, 3H); 7.21-7.31 (m, 2H).

Workup

  1. customThe solvent was removed in vacuo
  2. customto give a greenish-white semisolid
  3. filtration90% Hexanes and the resulting suspension was filtered through a pad of silica gel washing well with the same solvent system

Sources & evidence

ORD record
ord-5d15578de7914a1aab017a4093c39dd9
Source dataset
uspto-grants-2001_04
Patent number
US06214877B1

Reaction notes

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